Inverted Weibull Distribution

Shape parameter $c>0$ and $x>0$ . Then

$$\begin{eqnarray*} f\left(x;c\right) & = & cx^{-c-1}\exp\left(-x^{-c}\right)\\ F\left(x;c\right) & = & \exp\left(-x^{-c}\right)\\ G\left(q;c\right) & = & \left(-\log q\right)^{-1/c}\end{eqnarray*}$$

$$h\left[X\right]=1+\gamma+\frac{\gamma}{c}-\log\left(c\right)$$

where $\gamma$ is Euler’s constant.

Implementation: scipy.stats.invweibull